14323000111313 has 2 divisors, whose sum is σ = 14323000111314. Its totient is φ = 14323000111312.

The previous prime is 14323000111193. The next prime is 14323000111331. The reversal of 14323000111313 is 31311100032341.

Together with next prime (14323000111331) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9854752435984 + 4468247675329 = 3139228^2 + 2113823^2 .

It is an emirp because it is prime and its reverse (31311100032341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14323000111313 - 2¹² = 14323000107217 is a prime.

It is not a weakly prime, because it can be changed into another prime (14323000111363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161500055656 + 7161500055657.

It is an arithmetic number, because the mean of its divisors is an integer number (7161500055657).

Almost surely, 2^{14323000111313} is an apocalyptic number.

It is an amenable number.

14323000111313 is a deficient number, since it is larger than the sum of its proper divisors (1).

14323000111313 is an equidigital number, since it uses as much as digits as its factorization.

14323000111313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 14323000111313 its reverse (31311100032341), we get a palindrome (45634100143654).

The spelling of 14323000111313 in words is "fourteen trillion, three hundred twenty-three billion, one hundred eleven thousand, three hundred thirteen".