143230242520143 has 12 divisors (see below), whose sum is σ = 206991935500480. Its totient is φ = 95438917231776.

The previous prime is 143230242520139. The next prime is 143230242520151. The reversal of 143230242520143 is 341025242032341.

143230242520143 is a `hidden beast` number, since 1 + 4 + 3 + 23 + 0 + 2 + 425 + 201 + 4 + 3 = 666.

143230242520143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 143230242520143 - 2² = 143230242520139 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143230242520098 and 143230242520107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143230242520153) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3992573983 + ... + 3992609856.

Almost surely, 2^{143230242520143} is an apocalyptic number.

143230242520143 is a deficient number, since it is larger than the sum of its proper divisors (63761692980337).

143230242520143 is a wasteful number, since it uses less digits than its factorization.

143230242520143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7985185838 (or 7985185835 counting only the distinct ones).

The product of its (nonzero) digits is 138240, while the sum is 36.

Adding to 143230242520143 its reverse (341025242032341), we get a palindrome (484255484552484).

The spelling of 143230242520143 in words is "one hundred forty-three trillion, two hundred thirty billion, two hundred forty-two million, five hundred twenty thousand, one hundred forty-three".