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143230242520201 is a prime number
BaseRepresentation
bin100000100100010001100011…
…101110011111110010001001
3200210010200021212102201002111
4200210101203232133302021
5122233141014041121301
61224343022014502321
742112020634466044
oct4044214356376211
9623120255381074
10143230242520201
1141701671997171
1214092b925049a1
1361bc727c48825
1427525489ddc5b
151185b32236551
hex824463b9fc89

143230242520201 has 2 divisors, whose sum is σ = 143230242520202. Its totient is φ = 143230242520200.

The previous prime is 143230242520153. The next prime is 143230242520259. The reversal of 143230242520201 is 102025242032341.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96646614471801 + 46583628048400 = 9830901^2 + 6825220^2 .

It is an emirp because it is prime and its reverse (102025242032341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143230242520201 - 225 = 143230208965769 is a prime.

It is not a weakly prime, because it can be changed into another prime (143230242520291) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71615121260100 + 71615121260101.

It is an arithmetic number, because the mean of its divisors is an integer number (71615121260101).

Almost surely, 2143230242520201 is an apocalyptic number.

It is an amenable number.

143230242520201 is a deficient number, since it is larger than the sum of its proper divisors (1).

143230242520201 is an equidigital number, since it uses as much as digits as its factorization.

143230242520201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 143230242520201 its reverse (102025242032341), we get a palindrome (245255484552542).

The spelling of 143230242520201 in words is "one hundred forty-three trillion, two hundred thirty billion, two hundred forty-two million, five hundred twenty thousand, two hundred one".