143231034013441 has 4 divisors (see below), whose sum is σ = 156252037105584. Its totient is φ = 130210030921300.

The previous prime is 143231034013307. The next prime is 143231034013451. The reversal of 143231034013441 is 144310430132341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 143231034013441 - 2²⁷ = 143230899795713 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143231034013397 and 143231034013406.

It is not an unprimeable number, because it can be changed into a prime (143231034013451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6510501546055 + ... + 6510501546076.

It is an arithmetic number, because the mean of its divisors is an integer number (39063009276396).

Almost surely, 2^{143231034013441} is an apocalyptic number.

143231034013441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

143231034013441 is a deficient number, since it is larger than the sum of its proper divisors (13021003092143).

143231034013441 is a wasteful number, since it uses less digits than its factorization.

143231034013441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13021003092142.

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 143231034013441 its reverse (144310430132341), we get a palindrome (287541464145782).

The spelling of 143231034013441 in words is "one hundred forty-three trillion, two hundred thirty-one billion, thirty-four million, thirteen thousand, four hundred forty-one".