Search a number
-
+
14323220400121 is a prime number
BaseRepresentation
bin1101000001101110001001…
…1101101100011111111001
31212201021201212010112012221
43100123202131230133321
53334132423410300441
650243555134004041
73005550516413443
oct320334235543771
955637655115187
1014323220400121
114622497568206
121733b29646621
137cb89b6bc589
14377367471493
1519c8a6e058d1
hexd06e276c7f9

14323220400121 has 2 divisors, whose sum is σ = 14323220400122. Its totient is φ = 14323220400120.

The previous prime is 14323220400037. The next prime is 14323220400133. The reversal of 14323220400121 is 12100402232341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13826766286096 + 496454114025 = 3718436^2 + 704595^2 .

It is a cyclic number.

It is not a de Polignac number, because 14323220400121 - 211 = 14323220398073 is a prime.

It is not a weakly prime, because it can be changed into another prime (14323220400821) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161610200060 + 7161610200061.

It is an arithmetic number, because the mean of its divisors is an integer number (7161610200061).

Almost surely, 214323220400121 is an apocalyptic number.

It is an amenable number.

14323220400121 is a deficient number, since it is larger than the sum of its proper divisors (1).

14323220400121 is an equidigital number, since it uses as much as digits as its factorization.

14323220400121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14323220400121 its reverse (12100402232341), we get a palindrome (26423622632462).

The spelling of 14323220400121 in words is "fourteen trillion, three hundred twenty-three billion, two hundred twenty million, four hundred thousand, one hundred twenty-one".