14323220400037 has 2 divisors, whose sum is σ = 14323220400038. Its totient is φ = 14323220400036.

The previous prime is 14323220399947. The next prime is 14323220400121. The reversal of 14323220400037 is 73000402232341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13739965908516 + 583254491521 = 3706746^2 + 763711^2 .

It is an emirp because it is prime and its reverse (73000402232341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14323220400037 - 2¹¹ = 14323220397989 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14323220399981 and 14323220400008.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14323220490037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161610200018 + 7161610200019.

It is an arithmetic number, because the mean of its divisors is an integer number (7161610200019).

Almost surely, 2^{14323220400037} is an apocalyptic number.

It is an amenable number.

14323220400037 is a deficient number, since it is larger than the sum of its proper divisors (1).

14323220400037 is an equidigital number, since it uses as much as digits as its factorization.

14323220400037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 31.

Adding to 14323220400037 its reverse (73000402232341), we get a palindrome (87323622632378).

The spelling of 14323220400037 in words is "fourteen trillion, three hundred twenty-three billion, two hundred twenty million, four hundred thousand, thirty-seven".