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1432324232113 is a prime number
BaseRepresentation
bin10100110101111101001…
…011010101001110110001
312001221002010201220220211
4110311331023111032301
5141431400000411423
63014000051104121
7205324221043555
oct24657513251661
95057063656824
101432324232113
11502499763305
121b17165a2041
13a50b5679938
144d4795cd865
15273d0d4510d
hex14d7d2d53b1

1432324232113 has 2 divisors, whose sum is σ = 1432324232114. Its totient is φ = 1432324232112.

The previous prime is 1432324232089. The next prime is 1432324232153. The reversal of 1432324232113 is 3112324232341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1404526006129 + 27798225984 = 1185127^2 + 166728^2 .

It is a cyclic number.

It is not a de Polignac number, because 1432324232113 - 233 = 1423734297521 is a prime.

It is not a weakly prime, because it can be changed into another prime (1432324232153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 716162116056 + 716162116057.

It is an arithmetic number, because the mean of its divisors is an integer number (716162116057).

Almost surely, 21432324232113 is an apocalyptic number.

It is an amenable number.

1432324232113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1432324232113 is an equidigital number, since it uses as much as digits as its factorization.

1432324232113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 20736, while the sum is 31.

Adding to 1432324232113 its reverse (3112324232341), we get a palindrome (4544648464454).

The spelling of 1432324232113 in words is "one trillion, four hundred thirty-two billion, three hundred twenty-four million, two hundred thirty-two thousand, one hundred thirteen".