Base | Representation |
---|---|
bin | 1101000001101110100001… |
… | …1010100100000100010111 |
3 | 1212201021222211000001011011 |
4 | 3100123220122210010113 |
5 | 3334133124440224310 |
6 | 50244013101553051 |
7 | 3005553141151120 |
oct | 320335032440427 |
9 | 55637884001134 |
10 | 14323320242455 |
11 | 4622538961234 |
12 | 1733b56b75787 |
13 | 7cb8b62a9393 |
14 | 377376821047 |
15 | 19c8b0a7878a |
hex | d06e86a4117 |
14323320242455 has 32 divisors (see below), whose sum is σ = 19921175512704. Its totient is φ = 9682940123136.
The previous prime is 14323320242453. The next prime is 14323320242459. The reversal of 14323320242455 is 55424202332341.
It is not a de Polignac number, because 14323320242455 - 21 = 14323320242453 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14323320242453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4648549 + ... + 7089121.
It is an arithmetic number, because the mean of its divisors is an integer number (622536734772).
Almost surely, 214323320242455 is an apocalyptic number.
14323320242455 is a deficient number, since it is larger than the sum of its proper divisors (5597855270249).
14323320242455 is a wasteful number, since it uses less digits than its factorization.
14323320242455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2442955.
The product of its (nonzero) digits is 691200, while the sum is 40.
Adding to 14323320242455 its reverse (55424202332341), we get a palindrome (69747522574796).
The spelling of 14323320242455 in words is "fourteen trillion, three hundred twenty-three billion, three hundred twenty million, two hundred forty-two thousand, four hundred fifty-five".
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