Base | Representation |
---|---|
bin | 1000010101100111010… |
… | …1111100101001001101 |
3 | 111200201201122200022201 |
4 | 2011121311330221031 |
5 | 4321324224010041 |
6 | 145445404441501 |
7 | 13230436260043 |
oct | 2053165745115 |
9 | 450651580281 |
10 | 143241235021 |
11 | 55825a40a75 |
12 | 23917249291 |
13 | 1067a23a541 |
14 | 6d0bcac393 |
15 | 3ad5567631 |
hex | 2159d7ca4d |
143241235021 has 2 divisors, whose sum is σ = 143241235022. Its totient is φ = 143241235020.
The previous prime is 143241235003. The next prime is 143241235061. The reversal of 143241235021 is 120532142341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 129171954025 + 14069280996 = 359405^2 + 118614^2 .
It is a cyclic number.
It is not a de Polignac number, because 143241235021 - 211 = 143241232973 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143241235061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71620617510 + 71620617511.
It is an arithmetic number, because the mean of its divisors is an integer number (71620617511).
Almost surely, 2143241235021 is an apocalyptic number.
It is an amenable number.
143241235021 is a deficient number, since it is larger than the sum of its proper divisors (1).
143241235021 is an equidigital number, since it uses as much as digits as its factorization.
143241235021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 143241235021 its reverse (120532142341), we get a palindrome (263773377362).
The spelling of 143241235021 in words is "one hundred forty-three billion, two hundred forty-one million, two hundred thirty-five thousand, twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •