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14324242124343 = 323397522916151
BaseRepresentation
bin1101000001110001111101…
…0111010000111000110111
31212201101101001200111100210
43100130133113100320313
53334142021440434333
650244244353040503
73005615034054324
oct320343727207067
955641331614323
1014324242124343
114622971279798
121734173856133
137cba02294918
14377423035b4b
1519c916978a63
hexd071f5d0e37

14324242124343 has 16 divisors (see below), whose sum is σ = 19979580335616. Its totient is φ = 9111290997600.

The previous prime is 14324242124333. The next prime is 14324242124359. The reversal of 14324242124343 is 34342124242341.

It is not a de Polignac number, because 14324242124343 - 216 = 14324242058807 is a prime.

It is a super-2 number, since 2×143242421243432 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14324242124303) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 261430683 + ... + 261485468.

It is an arithmetic number, because the mean of its divisors is an integer number (1248723770976).

Almost surely, 214324242124343 is an apocalyptic number.

14324242124343 is a deficient number, since it is larger than the sum of its proper divisors (5655338211273).

14324242124343 is a wasteful number, since it uses less digits than its factorization.

14324242124343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 522916574.

The product of its digits is 442368, while the sum is 39.

Adding to 14324242124343 its reverse (34342124242341), we get a palindrome (48666366366684).

The spelling of 14324242124343 in words is "fourteen trillion, three hundred twenty-four billion, two hundred forty-two million, one hundred twenty-four thousand, three hundred forty-three".

Divisors: 1 3 23 69 397 1191 9131 27393 522916151 1568748453 12027071473 36081214419 207597711947 622793135841 4774747374781 14324242124343