Base | Representation |
---|---|
bin | 1101000001110001111101… |
… | …0111010000111000110111 |
3 | 1212201101101001200111100210 |
4 | 3100130133113100320313 |
5 | 3334142021440434333 |
6 | 50244244353040503 |
7 | 3005615034054324 |
oct | 320343727207067 |
9 | 55641331614323 |
10 | 14324242124343 |
11 | 4622971279798 |
12 | 1734173856133 |
13 | 7cba02294918 |
14 | 377423035b4b |
15 | 19c916978a63 |
hex | d071f5d0e37 |
14324242124343 has 16 divisors (see below), whose sum is σ = 19979580335616. Its totient is φ = 9111290997600.
The previous prime is 14324242124333. The next prime is 14324242124359. The reversal of 14324242124343 is 34342124242341.
It is not a de Polignac number, because 14324242124343 - 216 = 14324242058807 is a prime.
It is a super-2 number, since 2×143242421243432 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14324242124303) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 261430683 + ... + 261485468.
It is an arithmetic number, because the mean of its divisors is an integer number (1248723770976).
Almost surely, 214324242124343 is an apocalyptic number.
14324242124343 is a deficient number, since it is larger than the sum of its proper divisors (5655338211273).
14324242124343 is a wasteful number, since it uses less digits than its factorization.
14324242124343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 522916574.
The product of its digits is 442368, while the sum is 39.
Adding to 14324242124343 its reverse (34342124242341), we get a palindrome (48666366366684).
The spelling of 14324242124343 in words is "fourteen trillion, three hundred twenty-four billion, two hundred forty-two million, one hundred twenty-four thousand, three hundred forty-three".
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