Base | Representation |
---|---|
bin | 1101000001110001111110… |
… | …0000011100011110111110 |
3 | 1212201101101020012202212012 |
4 | 3100130133200130132332 |
5 | 3334142023044444014 |
6 | 50244244520411222 |
7 | 3005615063400236 |
oct | 320343740343676 |
9 | 55641336182765 |
10 | 14324244531134 |
11 | 4622972672a7a |
12 | 1734174616b12 |
13 | 7cba02928265 |
14 | 3774234a0cc6 |
15 | 19c916ca1c3e |
hex | d071f81c7be |
14324244531134 has 4 divisors (see below), whose sum is σ = 21486366796704. Its totient is φ = 7162122265566.
The previous prime is 14324244531101. The next prime is 14324244531169. The reversal of 14324244531134 is 43113544242341.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 14324244531091 and 14324244531100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3581061132782 + ... + 3581061132785.
It is an arithmetic number, because the mean of its divisors is an integer number (5371591699176).
Almost surely, 214324244531134 is an apocalyptic number.
14324244531134 is a deficient number, since it is larger than the sum of its proper divisors (7162122265570).
14324244531134 is an equidigital number, since it uses as much as digits as its factorization.
14324244531134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7162122265569.
The product of its digits is 552960, while the sum is 41.
Adding to 14324244531134 its reverse (43113544242341), we get a palindrome (57437788773475).
The spelling of 14324244531134 in words is "fourteen trillion, three hundred twenty-four billion, two hundred forty-four million, five hundred thirty-one thousand, one hundred thirty-four".
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