Base | Representation |
---|---|
bin | 1101000001110010010010… |
… | …1010011000001110111001 |
3 | 1212201101121020221220222111 |
4 | 3100130210222120032321 |
5 | 3334142212220134431 |
6 | 50244301250252321 |
7 | 3005620163504053 |
oct | 320344452301671 |
9 | 55641536856874 |
10 | 14324331021241 |
11 | 4622a074772aa |
12 | 17341995870a1 |
13 | 7cba1781b737 |
14 | 377430b768d3 |
15 | 19c91e6887b1 |
hex | d0724a983b9 |
14324331021241 has 2 divisors, whose sum is σ = 14324331021242. Its totient is φ = 14324331021240.
The previous prime is 14324331021151. The next prime is 14324331021293. The reversal of 14324331021241 is 14212013342341.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8815940797225 + 5508390224016 = 2969165^2 + 2346996^2 .
It is a cyclic number.
It is not a de Polignac number, because 14324331021241 - 219 = 14324330496953 is a prime.
It is not a weakly prime, because it can be changed into another prime (14324331027241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162165510620 + 7162165510621.
It is an arithmetic number, because the mean of its divisors is an integer number (7162165510621).
Almost surely, 214324331021241 is an apocalyptic number.
It is an amenable number.
14324331021241 is a deficient number, since it is larger than the sum of its proper divisors (1).
14324331021241 is an equidigital number, since it uses as much as digits as its factorization.
14324331021241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 14324331021241 its reverse (14212013342341), we get a palindrome (28536344363582).
The spelling of 14324331021241 in words is "fourteen trillion, three hundred twenty-four billion, three hundred thirty-one million, twenty-one thousand, two hundred forty-one".
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