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14325212540542 = 29967718632113
BaseRepresentation
bin1101000001110101100100…
…1101000110111001111110
31212201110212200200202010111
43100131121031012321332
53334201013402244132
650244524540300234
73005651056342141
oct320353115067176
955643780622114
1014325212540542
11462331a026852
1217343a484167a
137cbb283443a7
143774b5c82058
1519c971c64647
hexd0759346e7e

14325212540542 has 8 divisors (see below), whose sum is σ = 21489974737056. Its totient is φ = 7161887628192.

The previous prime is 14325212540533. The next prime is 14325212540557. The reversal of 14325212540542 is 24504521252341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 14325212540495 and 14325212540504.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 359296123 + ... + 359335990.

It is an arithmetic number, because the mean of its divisors is an integer number (2686246842132).

Almost surely, 214325212540542 is an apocalyptic number.

14325212540542 is a deficient number, since it is larger than the sum of its proper divisors (7164762196514).

14325212540542 is an equidigital number, since it uses as much as digits as its factorization.

14325212540542 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 718642082.

The product of its (nonzero) digits is 384000, while the sum is 40.

Adding to 14325212540542 its reverse (24504521252341), we get a palindrome (38829733792883).

The spelling of 14325212540542 in words is "fourteen trillion, three hundred twenty-five billion, two hundred twelve million, five hundred forty thousand, five hundred forty-two".

Divisors: 1 2 9967 19934 718632113 1437264226 7162606270271 14325212540542