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14325235542043 is a prime number
BaseRepresentation
bin1101000001110101101010…
…0100110110100000011011
31212201110221021222100020221
43100131122210312200123
53334201040244321133
650244531121300511
73005651456011666
oct320353244664033
955643837870227
1014325235542043
114623331007158
1217343b0494737
137cbb30038a4a
143774b8d4c6dd
1519c973ca9a2d
hexd075a93681b

14325235542043 has 2 divisors, whose sum is σ = 14325235542044. Its totient is φ = 14325235542042.

The previous prime is 14325235542041. The next prime is 14325235542067. The reversal of 14325235542043 is 34024553252341.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14325235542043 - 21 = 14325235542041 is a prime.

It is a super-2 number, since 2×143252355420432 (a number of 27 digits) contains 22 as substring.

Together with 14325235542041, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (14325235542041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162617771021 + 7162617771022.

It is an arithmetic number, because the mean of its divisors is an integer number (7162617771022).

Almost surely, 214325235542043 is an apocalyptic number.

14325235542043 is a deficient number, since it is larger than the sum of its proper divisors (1).

14325235542043 is an equidigital number, since it uses as much as digits as its factorization.

14325235542043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728000, while the sum is 43.

Adding to 14325235542043 its reverse (34024553252341), we get a palindrome (48349788794384).

The spelling of 14325235542043 in words is "fourteen trillion, three hundred twenty-five billion, two hundred thirty-five million, five hundred forty-two thousand, forty-three".