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14325420134119 is a prime number
BaseRepresentation
bin1101000001110110010110…
…0101000000111011100111
31212201111102011022120222111
43100131211211000323213
53334201430023242434
650245001313541451
73005656160014213
oct320354545007347
955644364276874
1014325420134119
114623416225996
121734442274887
137cbb5c359b23
143774d567d943
1519c9850bd964
hexd0765940ee7

14325420134119 has 2 divisors, whose sum is σ = 14325420134120. Its totient is φ = 14325420134118.

The previous prime is 14325420134101. The next prime is 14325420134197. The reversal of 14325420134119 is 91143102452341.

14325420134119 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14325420134119 - 213 = 14325420125927 is a prime.

It is a super-2 number, since 2×143254201341192 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14325420134719) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162710067059 + 7162710067060.

It is an arithmetic number, because the mean of its divisors is an integer number (7162710067060).

Almost surely, 214325420134119 is an apocalyptic number.

14325420134119 is a deficient number, since it is larger than the sum of its proper divisors (1).

14325420134119 is an equidigital number, since it uses as much as digits as its factorization.

14325420134119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 40.

The spelling of 14325420134119 in words is "fourteen trillion, three hundred twenty-five billion, four hundred twenty million, one hundred thirty-four thousand, one hundred nineteen".