14325420134121 has 4 divisors (see below), whose sum is σ = 19100560178832. Its totient is φ = 9550280089412.

The previous prime is 14325420134119. The next prime is 14325420134197. The reversal of 14325420134121 is 12143102452341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14325420134121 - 2¹ = 14325420134119 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14325420134101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2387570022351 + ... + 2387570022356.

It is an arithmetic number, because the mean of its divisors is an integer number (4775140044708).

Almost surely, 2^{14325420134121} is an apocalyptic number.

It is an amenable number.

14325420134121 is a deficient number, since it is larger than the sum of its proper divisors (4775140044711).

14325420134121 is an equidigital number, since it uses as much as digits as its factorization.

14325420134121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4775140044710.

The product of its (nonzero) digits is 23040, while the sum is 33.

Adding to 14325420134121 its reverse (12143102452341), we get a palindrome (26468522586462).

The spelling of 14325420134121 in words is "fourteen trillion, three hundred twenty-five billion, four hundred twenty million, one hundred thirty-four thousand, one hundred twenty-one".