Base | Representation |
---|---|
bin | 10100110110001010001… |
… | …110110001111111010011 |
3 | 12001221122101211200110111 |
4 | 110312022032301333103 |
5 | 141432322032141042 |
6 | 3014033513142151 |
7 | 205332520426135 |
oct | 24661216617723 |
9 | 5057571750414 |
10 | 1432543240147 |
11 | 5025a1349288 |
12 | 1b17779ba957 |
13 | a511bb5a9a6 |
14 | 4d49a71d055 |
15 | 273e51a6517 |
hex | 14d8a3b1fd3 |
1432543240147 has 2 divisors, whose sum is σ = 1432543240148. Its totient is φ = 1432543240146.
The previous prime is 1432543240099. The next prime is 1432543240181. The reversal of 1432543240147 is 7410423452341.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1432543240147 is a prime.
It is not a weakly prime, because it can be changed into another prime (1432543240187) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 716271620073 + 716271620074.
It is an arithmetic number, because the mean of its divisors is an integer number (716271620074).
Almost surely, 21432543240147 is an apocalyptic number.
1432543240147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1432543240147 is an equidigital number, since it uses as much as digits as its factorization.
1432543240147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 322560, while the sum is 40.
Adding to 1432543240147 its reverse (7410423452341), we get a palindrome (8842966692488).
The spelling of 1432543240147 in words is "one trillion, four hundred thirty-two billion, five hundred forty-three million, two hundred forty thousand, one hundred forty-seven".
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