Base | Representation |
---|---|
bin | 11010101011101110… |
… | …10000101011001111 |
3 | 1100222100212100001201 |
4 | 31111313100223033 |
5 | 213314303421341 |
6 | 10325300050331 |
7 | 1014666220432 |
oct | 152567205317 |
9 | 40870770051 |
10 | 14325451471 |
11 | 60913867a1 |
12 | 29396939a7 |
13 | 1473b7b506 |
14 | 99c7d3819 |
15 | 58c9bd331 |
hex | 355dd0acf |
14325451471 has 2 divisors, whose sum is σ = 14325451472. Its totient is φ = 14325451470.
The previous prime is 14325451457. The next prime is 14325451477. The reversal of 14325451471 is 17415452341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14325451471 - 29 = 14325450959 is a prime.
It is a super-3 number, since 3×143254514713 (a number of 31 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 14325451471.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14325451477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162725735 + 7162725736.
It is an arithmetic number, because the mean of its divisors is an integer number (7162725736).
Almost surely, 214325451471 is an apocalyptic number.
14325451471 is a deficient number, since it is larger than the sum of its proper divisors (1).
14325451471 is an equidigital number, since it uses as much as digits as its factorization.
14325451471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 67200, while the sum is 37.
The spelling of 14325451471 in words is "fourteen billion, three hundred twenty-five million, four hundred fifty-one thousand, four hundred seventy-one".
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