Base | Representation |
---|---|
bin | 1101000010000111100011… |
… | …1101111100000011100001 |
3 | 1212201221100011011112012111 |
4 | 3100201320331330003201 |
5 | 3334240410320332040 |
6 | 50251044002155321 |
7 | 3006211521443326 |
oct | 320417075740341 |
9 | 55657304145174 |
10 | 14330040402145 |
11 | 4625377250716 |
12 | 1735311652b41 |
13 | 7cc417622530 |
14 | 377813134b4d |
15 | 19cb55a16dea |
hex | d0878f7c0e1 |
14330040402145 has 32 divisors (see below), whose sum is σ = 18692719920000. Its totient is φ = 10482821867520.
The previous prime is 14330040402107. The next prime is 14330040402187. The reversal of 14330040402145 is 54120404003341.
It is not a de Polignac number, because 14330040402145 - 213 = 14330040393953 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 295556305 + ... + 295604785.
It is an arithmetic number, because the mean of its divisors is an integer number (584147497500).
Almost surely, 214330040402145 is an apocalyptic number.
It is an amenable number.
14330040402145 is a deficient number, since it is larger than the sum of its proper divisors (4362679517855).
14330040402145 is a wasteful number, since it uses less digits than its factorization.
14330040402145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 91105.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 14330040402145 its reverse (54120404003341), we get a palindrome (68450444405486).
The spelling of 14330040402145 in words is "fourteen trillion, three hundred thirty billion, forty million, four hundred two thousand, one hundred forty-five".
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