Search a number
-
+
14330044303 = 21116788273
BaseRepresentation
bin11010101100010001…
…10001111110001111
31100222200111200020121
431112020301332033
5213321442404203
610325542325411
71015053236551
oct152610617617
940880450217
1014330044303
116093a33423
12293b129867
131474ac8b73
1499d26b4d1
1558d0c90bd
hex356231f8f

14330044303 has 4 divisors (see below), whose sum is σ = 14336834688. Its totient is φ = 14323253920.

The previous prime is 14330044297. The next prime is 14330044349. The reversal of 14330044303 is 30344003341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14330044303 - 25 = 14330044271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14330044403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3392026 + ... + 3396247.

It is an arithmetic number, because the mean of its divisors is an integer number (3584208672).

Almost surely, 214330044303 is an apocalyptic number.

14330044303 is a deficient number, since it is larger than the sum of its proper divisors (6790385).

14330044303 is an equidigital number, since it uses as much as digits as its factorization.

14330044303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6790384.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 14330044303 its reverse (30344003341), we get a palindrome (44674047644).

The spelling of 14330044303 in words is "fourteen billion, three hundred thirty million, forty-four thousand, three hundred three".

Divisors: 1 2111 6788273 14330044303