Base | Representation |
---|---|
bin | 11010101100010001… |
… | …10011011001010111 |
3 | 1100222200111222020121 |
4 | 31112020303121113 |
5 | 213321443101020 |
6 | 10325542412411 |
7 | 1015053262552 |
oct | 152610633127 |
9 | 40880458217 |
10 | 14330050135 |
11 | 6093a37845 |
12 | 293b131107 |
13 | 1474acb70b |
14 | 99d26d699 |
15 | 58d0cabaa |
hex | 356233657 |
14330050135 has 16 divisors (see below), whose sum is σ = 18106536960. Its totient is φ = 10857417120.
The previous prime is 14330050129. The next prime is 14330050151. The reversal of 14330050135 is 53105003341.
It is not a de Polignac number, because 14330050135 - 25 = 14330050103 is a prime.
It is a super-2 number, since 2×143300501352 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 324174 + ... + 365716.
It is an arithmetic number, because the mean of its divisors is an integer number (1131658560).
Almost surely, 214330050135 is an apocalyptic number.
14330050135 is a deficient number, since it is larger than the sum of its proper divisors (3776486825).
14330050135 is a wasteful number, since it uses less digits than its factorization.
14330050135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45198.
The product of its (nonzero) digits is 2700, while the sum is 25.
Adding to 14330050135 its reverse (53105003341), we get a palindrome (67435053476).
The spelling of 14330050135 in words is "fourteen billion, three hundred thirty million, fifty thousand, one hundred thirty-five".
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