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143301431145 = 3582711551909
BaseRepresentation
bin1000010101110101101…
…1100100111101101001
3111200212220220221212210
42011131123210331221
54321440131244040
6145455354555333
713232100031665
oct2053533447551
9450786827783
10143301431145
1155856a16234
1223933438b49
1310689855852
146d15c9b8a5
153ada9a8480
hex215d6e4f69

143301431145 has 16 divisors (see below), whose sum is σ = 229559555520. Its totient is φ = 76335008064.

The previous prime is 143301431107. The next prime is 143301431149. The reversal of 143301431145 is 541134103341.

It is not a de Polignac number, because 143301431145 - 215 = 143301398377 is a prime.

It is a super-2 number, since 2×1433014311452 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (143301431149) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5763550 + ... + 5788359.

It is an arithmetic number, because the mean of its divisors is an integer number (14347472220).

Almost surely, 2143301431145 is an apocalyptic number.

143301431145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

143301431145 is a deficient number, since it is larger than the sum of its proper divisors (86258124375).

143301431145 is a wasteful number, since it uses less digits than its factorization.

143301431145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11552744.

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 143301431145 its reverse (541134103341), we get a palindrome (684435534486).

The spelling of 143301431145 in words is "one hundred forty-three billion, three hundred one million, four hundred thirty-one thousand, one hundred forty-five".

Divisors: 1 3 5 15 827 2481 4135 12405 11551909 34655727 57759545 173278635 9553428743 28660286229 47767143715 143301431145