Base | Representation |
---|---|
bin | 1101000010001001000001… |
… | …1001101001010001111010 |
3 | 1212201222100112221001122210 |
4 | 3100202100121221101322 |
5 | 3334242211441304432 |
6 | 50251151004355550 |
7 | 3006224334201420 |
oct | 320422031512172 |
9 | 55658315831583 |
10 | 14330433541242 |
11 | 462555915a965 |
12 | 1735401245bb6 |
13 | 7cc47ac01010 |
14 | 37784d431110 |
15 | 19cb7a2c28cc |
hex | d089066947a |
14330433541242 has 64 divisors (see below), whose sum is σ = 35940477807360. Its totient is φ = 3708144520704.
The previous prime is 14330433541231. The next prime is 14330433541271. The reversal of 14330433541242 is 24214533403341.
It is a super-2 number, since 2×143304335412422 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a self number, because there is not a number n which added to its sum of digits gives 14330433541242.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 247576867 + ... + 247634742.
It is an arithmetic number, because the mean of its divisors is an integer number (561569965740).
Almost surely, 214330433541242 is an apocalyptic number.
14330433541242 is an abundant number, since it is smaller than the sum of its proper divisors (21610044266118).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14330433541242 is a wasteful number, since it uses less digits than its factorization.
14330433541242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 495211687.
The product of its (nonzero) digits is 414720, while the sum is 39.
Adding to 14330433541242 its reverse (24214533403341), we get a palindrome (38544966944583).
The spelling of 14330433541242 in words is "fourteen trillion, three hundred thirty billion, four hundred thirty-three million, five hundred forty-one thousand, two hundred forty-two".
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