14331022013311 has 2 divisors, whose sum is σ = 14331022013312. Its totient is φ = 14331022013310.

The previous prime is 14331022013257. The next prime is 14331022013327. The reversal of 14331022013311 is 11331022013341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14331022013311 - 2⁷ = 14331022013183 is a prime.

It is a super-2 number, since 2×14331022013311² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14331022013411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7165511006655 + 7165511006656.

It is an arithmetic number, because the mean of its divisors is an integer number (7165511006656).

Almost surely, 2^{14331022013311} is an apocalyptic number.

14331022013311 is a deficient number, since it is larger than the sum of its proper divisors (1).

14331022013311 is an equidigital number, since it uses as much as digits as its factorization.

14331022013311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 14331022013311 its reverse (11331022013341), we get a palindrome (25662044026652).

The spelling of 14331022013311 in words is "fourteen trillion, three hundred thirty-one billion, twenty-two million, thirteen thousand, three hundred eleven".