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143310402034 = 271655201017
BaseRepresentation
bin1000010101110111110…
…1110011000111110010
3111200220112210201121221
42011131331303013302
54321444430331114
6145500315135254
713232236214122
oct2053575630762
9450815721557
10143310402034
1155860a93198
122393644452a
131068b676b77
146d17154c82
153adb67b524
hex215df731f2

143310402034 has 4 divisors (see below), whose sum is σ = 214965603054. Its totient is φ = 71655201016.

The previous prime is 143310401987. The next prime is 143310402043. The reversal of 143310402034 is 430204013341.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 430204013341 = 676420955423.

It can be written as a sum of positive squares in only one way, i.e., 143296317025 + 14085009 = 378545^2 + 3753^2 .

It is a super-2 number, since 2×1433104020342 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35827600507 + ... + 35827600510.

Almost surely, 2143310402034 is an apocalyptic number.

143310402034 is a deficient number, since it is larger than the sum of its proper divisors (71655201020).

143310402034 is an equidigital number, since it uses as much as digits as its factorization.

143310402034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71655201019.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 143310402034 its reverse (430204013341), we get a palindrome (573514415375).

The spelling of 143310402034 in words is "one hundred forty-three billion, three hundred ten million, four hundred two thousand, thirty-four".

Divisors: 1 2 71655201017 143310402034