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143311201993 = 433332818651
BaseRepresentation
bin1000010101111000000…
…0110110011011001001
3111200220121022100222001
42011132000312123021
54322000131430433
6145500344231001
713232246055301
oct2053600663311
9450817270861
10143311201993
115586148a213
122393676b461
131068b89700b
146d172c2601
153adb78857d
hex215e0366c9

143311201993 has 4 divisors (see below), whose sum is σ = 146644020688. Its totient is φ = 139978383300.

The previous prime is 143311201991. The next prime is 143311201997. The reversal of 143311201993 is 399102113341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 143311201993 - 21 = 143311201991 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143311201991) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1666409283 + ... + 1666409368.

It is an arithmetic number, because the mean of its divisors is an integer number (36661005172).

Almost surely, 2143311201993 is an apocalyptic number.

It is an amenable number.

143311201993 is a deficient number, since it is larger than the sum of its proper divisors (3332818695).

143311201993 is an equidigital number, since it uses as much as digits as its factorization.

143311201993 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3332818694.

The product of its (nonzero) digits is 17496, while the sum is 37.

The spelling of 143311201993 in words is "one hundred forty-three billion, three hundred eleven million, two hundred one thousand, nine hundred ninety-three".

Divisors: 1 43 3332818651 143311201993