Base | Representation |
---|---|
bin | 1000010101111000010… |
… | …1001010110010110001 |
3 | 111200220200102212210021 |
4 | 2011132011022302301 |
5 | 4322000424142001 |
6 | 145500424403441 |
7 | 13232261511514 |
oct | 2053605126261 |
9 | 450820385707 |
10 | 143312334001 |
11 | 55862092761 |
12 | 23937016581 |
13 | 1068bba2345 |
14 | 6d174d8d7b |
15 | 3adb90dba1 |
hex | 215e14acb1 |
143312334001 has 2 divisors, whose sum is σ = 143312334002. Its totient is φ = 143312334000.
The previous prime is 143312333963. The next prime is 143312334013. The reversal of 143312334001 is 100433213341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 140040608400 + 3271725601 = 374220^2 + 57199^2 .
It is an emirp because it is prime and its reverse (100433213341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 143312334001 - 27 = 143312333873 is a prime.
It is not a weakly prime, because it can be changed into another prime (143312334301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71656167000 + 71656167001.
It is an arithmetic number, because the mean of its divisors is an integer number (71656167001).
Almost surely, 2143312334001 is an apocalyptic number.
It is an amenable number.
143312334001 is a deficient number, since it is larger than the sum of its proper divisors (1).
143312334001 is an equidigital number, since it uses as much as digits as its factorization.
143312334001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 143312334001 its reverse (100433213341), we get a palindrome (243745547342).
The spelling of 143312334001 in words is "one hundred forty-three billion, three hundred twelve million, three hundred thirty-four thousand, one".
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