Base | Representation |
---|---|
bin | 100000100101100101101010… |
… | …000001010111101001100010 |
3 | 200210110022101000200010111111 |
4 | 200211211222001113221202 |
5 | 122241130432331203010 |
6 | 1224452314231333534 |
7 | 42121365435254302 |
oct | 4045455201275142 |
9 | 623408330603444 |
10 | 143320542444130 |
11 | 4173699a93a577 |
12 | 140a85938212aa |
13 | 61c80b8c4008c |
14 | 2756a73691602 |
15 | 1188169aa958a |
hex | 82596a057a62 |
143320542444130 has 8 divisors (see below), whose sum is σ = 257976976399452. Its totient is φ = 57328216977648.
The previous prime is 143320542444127. The next prime is 143320542444137. The reversal of 143320542444130 is 31444245023341.
It can be written as a sum of positive squares in 2 ways, for example, as 141931696693081 + 1388845751049 = 11913509^2 + 1178493^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is not an unprimeable number, because it can be changed into a prime (143320542444137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7166027122197 + ... + 7166027122216.
Almost surely, 2143320542444130 is an apocalyptic number.
143320542444130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
143320542444130 is a deficient number, since it is larger than the sum of its proper divisors (114656433955322).
143320542444130 is a wasteful number, since it uses less digits than its factorization.
143320542444130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14332054244420.
The product of its (nonzero) digits is 552960, while the sum is 40.
Adding to 143320542444130 its reverse (31444245023341), we get a palindrome (174764787467471).
The spelling of 143320542444130 in words is "one hundred forty-three trillion, three hundred twenty billion, five hundred forty-two million, four hundred forty-four thousand, one hundred thirty".
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