Base | Representation |
---|---|
bin | 1101000010001111101101… |
… | …1110101101011100001101 |
3 | 1212202010222202100012110211 |
4 | 3100203323132231130031 |
5 | 3334304401341443432 |
6 | 50252045141402421 |
7 | 3006320010126265 |
oct | 320437336553415 |
9 | 55663882305424 |
10 | 14332230031117 |
11 | 46262a0237339 |
12 | 1735822a09411 |
13 | 7cc6a616248b |
14 | 37797dc727a5 |
15 | 19cc32d85d47 |
hex | d08fb7ad70d |
14332230031117 has 2 divisors, whose sum is σ = 14332230031118. Its totient is φ = 14332230031116.
The previous prime is 14332230031109. The next prime is 14332230031129. The reversal of 14332230031117 is 71113003223341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14323038207241 + 9191823876 = 3784579^2 + 95874^2 .
It is a cyclic number.
It is not a de Polignac number, because 14332230031117 - 23 = 14332230031109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14332230031417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7166115015558 + 7166115015559.
It is an arithmetic number, because the mean of its divisors is an integer number (7166115015559).
Almost surely, 214332230031117 is an apocalyptic number.
It is an amenable number.
14332230031117 is a deficient number, since it is larger than the sum of its proper divisors (1).
14332230031117 is an equidigital number, since it uses as much as digits as its factorization.
14332230031117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9072, while the sum is 31.
Adding to 14332230031117 its reverse (71113003223341), we get a palindrome (85445233254458).
The spelling of 14332230031117 in words is "fourteen trillion, three hundred thirty-two billion, two hundred thirty million, thirty-one thousand, one hundred seventeen".
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