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143323232132321 is a prime number
BaseRepresentation
bin100000100101101000001010…
…010101101101110011100001
3200210110120022110210110001122
4200211220022111231303201
5122241201434411213241
61224453441152542025
742121522205241653
oct4045501225556341
9623416273713048
10143323232132321
114173805012307a
12140a9004551915
1361c8427256057
142756c4a99c6d3
151188275ca404b
hex825a0a56dce1

143323232132321 has 2 divisors, whose sum is σ = 143323232132322. Its totient is φ = 143323232132320.

The previous prime is 143323232132309. The next prime is 143323232132323. The reversal of 143323232132321 is 123231232323341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 142021205080225 + 1302027052096 = 11917265^2 + 1141064^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143323232132321 is a prime.

Together with 143323232132323, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (143323232132323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71661616066160 + 71661616066161.

It is an arithmetic number, because the mean of its divisors is an integer number (71661616066161).

Almost surely, 2143323232132321 is an apocalyptic number.

It is an amenable number.

143323232132321 is a deficient number, since it is larger than the sum of its proper divisors (1).

143323232132321 is an equidigital number, since it uses as much as digits as its factorization.

143323232132321 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 93312, while the sum is 35.

Adding to 143323232132321 its reverse (123231232323341), we get a palindrome (266554464455662).

The spelling of 143323232132321 in words is "one hundred forty-three trillion, three hundred twenty-three billion, two hundred thirty-two million, one hundred thirty-two thousand, three hundred twenty-one".