Base | Representation |
---|---|
bin | 1101000010010000100010… |
… | …0111100001011011011111 |
3 | 1212202011120010002101111211 |
4 | 3100210020213201123133 |
5 | 3334310324303220043 |
6 | 50252123053525251 |
7 | 3006325324455364 |
oct | 320441047413337 |
9 | 55664503071454 |
10 | 14332450445023 |
11 | 46263a36a2597 |
12 | 17358847a3827 |
13 | 7cc70ca163c9 |
14 | 3779a124a46b |
15 | 19cc473c3a9d |
hex | d09089e16df |
14332450445023 has 2 divisors, whose sum is σ = 14332450445024. Its totient is φ = 14332450445022.
The previous prime is 14332450445011. The next prime is 14332450445069. The reversal of 14332450445023 is 32054405423341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14332450445023 - 221 = 14332448347871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14332450445323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7166225222511 + 7166225222512.
It is an arithmetic number, because the mean of its divisors is an integer number (7166225222512).
Almost surely, 214332450445023 is an apocalyptic number.
14332450445023 is a deficient number, since it is larger than the sum of its proper divisors (1).
14332450445023 is an equidigital number, since it uses as much as digits as its factorization.
14332450445023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 691200, while the sum is 40.
Adding to 14332450445023 its reverse (32054405423341), we get a palindrome (46386855868364).
The spelling of 14332450445023 in words is "fourteen trillion, three hundred thirty-two billion, four hundred fifty million, four hundred forty-five thousand, twenty-three".
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