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143330111053 is a prime number
BaseRepresentation
bin1000010101111100100…
…0111110111001001101
3111200221220220001022121
42011133020332321031
54322020002023203
6145502301412541
713232565561613
oct2053710767115
9450856801277
10143330111053
1155871124938
1223940b6a151
13106927879cc
146d19a056b3
153add2710bd
hex215f23ee4d

143330111053 has 2 divisors, whose sum is σ = 143330111054. Its totient is φ = 143330111052.

The previous prime is 143330111033. The next prime is 143330111117. The reversal of 143330111053 is 350111033341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 143248624324 + 81486729 = 378482^2 + 9027^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143330111053 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143330111033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71665055526 + 71665055527.

It is an arithmetic number, because the mean of its divisors is an integer number (71665055527).

Almost surely, 2143330111053 is an apocalyptic number.

It is an amenable number.

143330111053 is a deficient number, since it is larger than the sum of its proper divisors (1).

143330111053 is an equidigital number, since it uses as much as digits as its factorization.

143330111053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 143330111053 its reverse (350111033341), we get a palindrome (493441144394).

The spelling of 143330111053 in words is "one hundred forty-three billion, three hundred thirty million, one hundred eleven thousand, fifty-three".