Base | Representation |
---|---|
bin | 11010101100101000… |
… | …10000100010111011 |
3 | 1100222220011112120002 |
4 | 31112110100202323 |
5 | 213323230144430 |
6 | 10330131023215 |
7 | 1015120640603 |
oct | 152624204273 |
9 | 40886145502 |
10 | 14333053115 |
11 | 60956a8a47 |
12 | 294013ab0b |
13 | 1475610524 |
14 | 99d811c03 |
15 | 58d4c0845 |
hex | 3565108bb |
14333053115 has 8 divisors (see below), whose sum is σ = 17211509808. Its totient is φ = 11458545120.
The previous prime is 14333053109. The next prime is 14333053151. The reversal of 14333053115 is 51135033341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14333053115 - 24 = 14333053099 is a prime.
It is a super-2 number, since 2×143330531152 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 979181 + ... + 993710.
It is an arithmetic number, because the mean of its divisors is an integer number (2151438726).
Almost surely, 214333053115 is an apocalyptic number.
14333053115 is a deficient number, since it is larger than the sum of its proper divisors (2878456693).
14333053115 is a wasteful number, since it uses less digits than its factorization.
14333053115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1974349.
The product of its (nonzero) digits is 8100, while the sum is 29.
Adding to 14333053115 its reverse (51135033341), we get a palindrome (65468086456).
The spelling of 14333053115 in words is "fourteen billion, three hundred thirty-three million, fifty-three thousand, one hundred fifteen".
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