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14334010434011 = 23623217844957
BaseRepresentation
bin1101000010010110010110…
…0110011010000111011011
31212202022120211111001002202
43100211211212122013123
53334322023132342021
650252541541520415
73006412066243262
oct320454546320733
955668524431082
1014334010434011
114627024226394
12173603b11310b
137cc8cac80608
14377aac4c75d9
1519ccd931ca0b
hexd096599a1db

14334010434011 has 4 divisors (see below), whose sum is σ = 14957228278992. Its totient is φ = 13710792589032.

The previous prime is 14334010433993. The next prime is 14334010434047. The reversal of 14334010434011 is 11043401043341.

14334010434011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14334010434011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14334010434311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 311608922456 + ... + 311608922501.

It is an arithmetic number, because the mean of its divisors is an integer number (3739307069748).

Almost surely, 214334010434011 is an apocalyptic number.

14334010434011 is a deficient number, since it is larger than the sum of its proper divisors (623217844981).

14334010434011 is an equidigital number, since it uses as much as digits as its factorization.

14334010434011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 623217844980.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 14334010434011 its reverse (11043401043341), we get a palindrome (25377411477352).

The spelling of 14334010434011 in words is "fourteen trillion, three hundred thirty-four billion, ten million, four hundred thirty-four thousand, eleven".

Divisors: 1 23 623217844957 14334010434011