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143340243243347 is a prime number
BaseRepresentation
bin100000100101111000000000…
…010001111101000101010011
3200210112012020000012102102202
4200211320000101331011103
5122241441304232241342
61224505333152033415
742122663565300563
oct4045700021750523
9623465200172382
10143340243243347
114174428a490617
12140b037153286b
1361c9c08639917
1427579c1d30da3
15118891e423332
hex825e0047d153

143340243243347 has 2 divisors, whose sum is σ = 143340243243348. Its totient is φ = 143340243243346.

The previous prime is 143340243243319. The next prime is 143340243243367. The reversal of 143340243243347 is 743342342043341.

It is a strong prime.

It is an emirp because it is prime and its reverse (743342342043341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143340243243347 - 210 = 143340243242323 is a prime.

It is not a weakly prime, because it can be changed into another prime (143340243243367) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71670121621673 + 71670121621674.

It is an arithmetic number, because the mean of its divisors is an integer number (71670121621674).

Almost surely, 2143340243243347 is an apocalyptic number.

143340243243347 is a deficient number, since it is larger than the sum of its proper divisors (1).

143340243243347 is an equidigital number, since it uses as much as digits as its factorization.

143340243243347 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6967296, while the sum is 47.

Adding to 143340243243347 its reverse (743342342043341), we get a palindrome (886682585286688).

The spelling of 143340243243347 in words is "one hundred forty-three trillion, three hundred forty billion, two hundred forty-three million, two hundred forty-three thousand, three hundred forty-seven".