Base | Representation |
---|---|
bin | 100000100101111000000000… |
… | …010001111101000101010011 |
3 | 200210112012020000012102102202 |
4 | 200211320000101331011103 |
5 | 122241441304232241342 |
6 | 1224505333152033415 |
7 | 42122663565300563 |
oct | 4045700021750523 |
9 | 623465200172382 |
10 | 143340243243347 |
11 | 4174428a490617 |
12 | 140b037153286b |
13 | 61c9c08639917 |
14 | 27579c1d30da3 |
15 | 118891e423332 |
hex | 825e0047d153 |
143340243243347 has 2 divisors, whose sum is σ = 143340243243348. Its totient is φ = 143340243243346.
The previous prime is 143340243243319. The next prime is 143340243243367. The reversal of 143340243243347 is 743342342043341.
It is a strong prime.
It is an emirp because it is prime and its reverse (743342342043341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 143340243243347 - 210 = 143340243242323 is a prime.
It is not a weakly prime, because it can be changed into another prime (143340243243367) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71670121621673 + 71670121621674.
It is an arithmetic number, because the mean of its divisors is an integer number (71670121621674).
Almost surely, 2143340243243347 is an apocalyptic number.
143340243243347 is a deficient number, since it is larger than the sum of its proper divisors (1).
143340243243347 is an equidigital number, since it uses as much as digits as its factorization.
143340243243347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6967296, while the sum is 47.
Adding to 143340243243347 its reverse (743342342043341), we get a palindrome (886682585286688).
The spelling of 143340243243347 in words is "one hundred forty-three trillion, three hundred forty billion, two hundred forty-three million, two hundred forty-three thousand, three hundred forty-seven".
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