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143340243243319 is a prime number
BaseRepresentation
bin100000100101111000000000…
…010001111101000100110111
3200210112012020000012102101201
4200211320000101331010313
5122241441304232241234
61224505333152033331
742122663565300523
oct4045700021750467
9623465200172351
10143340243243319
114174428a4905a1
12140b0371532847
1361c9c086398c5
1427579c1d30d83
15118891e423314
hex825e0047d137

143340243243319 has 2 divisors, whose sum is σ = 143340243243320. Its totient is φ = 143340243243318.

The previous prime is 143340243243227. The next prime is 143340243243347. The reversal of 143340243243319 is 913342342043341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 143340243243319 - 219 = 143340242719031 is a prime.

It is a super-2 number, since 2×1433402432433192 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143340243249319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71670121621659 + 71670121621660.

It is an arithmetic number, because the mean of its divisors is an integer number (71670121621660).

Almost surely, 2143340243243319 is an apocalyptic number.

143340243243319 is a deficient number, since it is larger than the sum of its proper divisors (1).

143340243243319 is an equidigital number, since it uses as much as digits as its factorization.

143340243243319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2239488, while the sum is 46.

The spelling of 143340243243319 in words is "one hundred forty-three trillion, three hundred forty billion, two hundred forty-three million, two hundred forty-three thousand, three hundred nineteen".