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14334414053 is a prime number
BaseRepresentation
bin11010101100110010…
…11100110011100101
31100222222201200102012
431112121130303211
5213324102222203
610330220124005
71015135336421
oct152631346345
940888650365
1014334414053
116096448493
122940696605
131475998b0b
1499da87b81
1558d68dbd8
hex35665cce5

14334414053 has 2 divisors, whose sum is σ = 14334414054. Its totient is φ = 14334414052.

The previous prime is 14334414049. The next prime is 14334414077. The reversal of 14334414053 is 35041443341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10212517249 + 4121896804 = 101057^2 + 64202^2 .

It is a cyclic number.

It is not a de Polignac number, because 14334414053 - 22 = 14334414049 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14334404053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7167207026 + 7167207027.

It is an arithmetic number, because the mean of its divisors is an integer number (7167207027).

Almost surely, 214334414053 is an apocalyptic number.

It is an amenable number.

14334414053 is a deficient number, since it is larger than the sum of its proper divisors (1).

14334414053 is an equidigital number, since it uses as much as digits as its factorization.

14334414053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34560, while the sum is 32.

Adding to 14334414053 its reverse (35041443341), we get a palindrome (49375857394).

The spelling of 14334414053 in words is "fourteen billion, three hundred thirty-four million, four hundred fourteen thousand, fifty-three".