Base | Representation |
---|---|
bin | 10100110111000000010… |
… | …101101110101100101100 |
3 | 12002000222200000020212112 |
4 | 110313000111232230230 |
5 | 141441201431000330 |
6 | 3014303542223152 |
7 | 205364152504526 |
oct | 24670025565454 |
9 | 5060880006775 |
10 | 1433451031340 |
11 | 502a17812239 |
12 | 1b198ba24ab8 |
13 | a5234c51743 |
14 | 4d545106a16 |
15 | 27449c21795 |
hex | 14dc056eb2c |
1433451031340 has 24 divisors (see below), whose sum is σ = 3022842352320. Its totient is φ = 570981329408.
The previous prime is 1433451031339. The next prime is 1433451031393. The reversal of 1433451031340 is 431301543341.
It is a junction number, because it is equal to n+sod(n) for n = 1433451031297 and 1433451031306.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 149937797 + ... + 149947356.
It is an arithmetic number, because the mean of its divisors is an integer number (125951764680).
Almost surely, 21433451031340 is an apocalyptic number.
1433451031340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1433451031340 is an abundant number, since it is smaller than the sum of its proper divisors (1589391320980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1433451031340 is a wasteful number, since it uses less digits than its factorization.
1433451031340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 299885401 (or 299885399 counting only the distinct ones).
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 1433451031340 its reverse (431301543341), we get a palindrome (1864752574681).
The spelling of 1433451031340 in words is "one trillion, four hundred thirty-three billion, four hundred fifty-one million, thirty-one thousand, three hundred forty".
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