14335403345 has 4 divisors (see below), whose sum is σ = 17202484020. Its totient is φ = 11468322672.

The previous prime is 14335403261. The next prime is 14335403351. The reversal of 14335403345 is 54330453341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6305630464 + 8029772881 = 79408^2 + 89609^2 .

It is a cyclic number.

It is not a de Polignac number, because 14335403345 - 2¹² = 14335399249 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1433540330 + ... + 1433540339.

It is an arithmetic number, because the mean of its divisors is an integer number (4300621005).

Almost surely, 2^14335403345 is an apocalyptic number.

It is an amenable number.

14335403345 is a deficient number, since it is larger than the sum of its proper divisors (2867080675).

14335403345 is an equidigital number, since it uses as much as digits as its factorization.

14335403345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2867080674.

The product of its (nonzero) digits is 129600, while the sum is 35.

Adding to 14335403345 its reverse (54330453341), we get a palindrome (68665856686).

The spelling of 14335403345 in words is "fourteen billion, three hundred thirty-five million, four hundred three thousand, three hundred forty-five".