Base | Representation |
---|---|
bin | 11010101101000011… |
… | …01100001010011001 |
3 | 1101000010210102110010 |
4 | 31112201230022121 |
5 | 213330130332410 |
6 | 10330334312133 |
7 | 1015162604100 |
oct | 152641541231 |
9 | 41003712403 |
10 | 14336574105 |
11 | 6097693357 |
12 | 2941358649 |
13 | 1476274059 |
14 | 9a008b037 |
15 | 58d968c20 |
hex | 35686c299 |
14336574105 has 48 divisors (see below), whose sum is σ = 27121103424. Its totient is φ = 6446401920.
The previous prime is 14336574097. The next prime is 14336574121. The reversal of 14336574105 is 50147563341.
It is not a de Polignac number, because 14336574105 - 23 = 14336574097 is a prime.
It is a super-3 number, since 3×143365741053 (a number of 31 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 115047 + ... + 204716.
It is an arithmetic number, because the mean of its divisors is an integer number (565022988).
Almost surely, 214336574105 is an apocalyptic number.
14336574105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
14336574105 is a deficient number, since it is larger than the sum of its proper divisors (12784529319).
14336574105 is a wasteful number, since it uses less digits than its factorization.
14336574105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 319846 (or 319839 counting only the distinct ones).
The product of its (nonzero) digits is 151200, while the sum is 39.
It can be divided in two parts, 143365 and 74105, that added together give a triangular number (217470 = T659).
The spelling of 14336574105 in words is "fourteen billion, three hundred thirty-six million, five hundred seventy-four thousand, one hundred five".
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