1434000401 has 4 divisors (see below), whose sum is σ = 1434126900. Its totient is φ = 1433873904.

The previous prime is 1434000391. The next prime is 1434000427. The reversal of 1434000401 is 1040004341.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1040004341 = 283 ⋅3674927.

It can be written as a sum of positive squares in 2 ways, for example, as 46512400 + 1387488001 = 6820^2 + 37249^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1434000401 is a prime.

It is a super-3 number, since 3×1434000401³ (a number of 28 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1434000401.

It is not an unprimeable number, because it can be changed into a prime (1434000301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44366 + ... + 69543.

It is an arithmetic number, because the mean of its divisors is an integer number (358531725).

Almost surely, 2^1434000401 is an apocalyptic number.

It is an amenable number.

1434000401 is a deficient number, since it is larger than the sum of its proper divisors (126499).

1434000401 is a wasteful number, since it uses less digits than its factorization.

1434000401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 126498.

The product of its (nonzero) digits is 192, while the sum is 17.

The square root of 1434000401 is about 37868.1977522036. The cubic root of 1434000401 is about 1127.6727630083.

Adding to 1434000401 its reverse (1040004341), we get a palindrome (2474004742).

The spelling of 1434000401 in words is "one billion, four hundred thirty-four million, four hundred one", and thus it is an aban number.