Search a number
-
+
1434003011953 is a prime number
BaseRepresentation
bin10100110111100001001…
…111010111100101110001
312002002102010122202220221
4110313201033113211301
5141443314232340303
63014434421133041
7205413634325461
oct24674117274561
95062363582827
101434003011953
11503180352466
121b1b0485a181
13a52c24065a5
144d59854dba1
152747d4064bd
hex14de13d7971

1434003011953 has 2 divisors, whose sum is σ = 1434003011954. Its totient is φ = 1434003011952.

The previous prime is 1434003011921. The next prime is 1434003011963. The reversal of 1434003011953 is 3591103004341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1400963406129 + 33039605824 = 1183623^2 + 181768^2 .

It is an emirp because it is prime and its reverse (3591103004341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1434003011953 - 25 = 1434003011921 is a prime.

It is not a weakly prime, because it can be changed into another prime (1434003011963) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717001505976 + 717001505977.

It is an arithmetic number, because the mean of its divisors is an integer number (717001505977).

Almost surely, 21434003011953 is an apocalyptic number.

It is an amenable number.

1434003011953 is a deficient number, since it is larger than the sum of its proper divisors (1).

1434003011953 is an equidigital number, since it uses as much as digits as its factorization.

1434003011953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19440, while the sum is 34.

The spelling of 1434003011953 in words is "one trillion, four hundred thirty-four billion, three million, eleven thousand, nine hundred fifty-three".