1434011311 has 2 divisors, whose sum is σ = 1434011312. Its totient is φ = 1434011310.

The previous prime is 1434011297. The next prime is 1434011317. The reversal of 1434011311 is 1131104341.

It is a strong prime.

It is an emirp because it is prime and its reverse (1131104341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1434011311 - 2⁵ = 1434011279 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1434011317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717005655 + 717005656.

It is an arithmetic number, because the mean of its divisors is an integer number (717005656).

Almost surely, 2^1434011311 is an apocalyptic number.

1434011311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1434011311 is an equidigital number, since it uses as much as digits as its factorization.

1434011311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

The square root of 1434011311 is about 37868.3418042037. The cubic root of 1434011311 is about 1127.6756228119.

Adding to 1434011311 its reverse (1131104341), we get a palindrome (2565115652).

It can be divided in two parts, 14340 and 11311, that added together give a triangular number (25651 = T₂₂₆).

The spelling of 1434011311 in words is "one billion, four hundred thirty-four million, eleven thousand, three hundred eleven".