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1434014113 = 71910782061
BaseRepresentation
bin101010101111001…
…0101000110100001
310200221100110112211
41111132111012201
510414101422423
6354143522121
750351630110
oct12536250641
93627313484
101434014113
11676511034
123402b9341
1319b12a87c
14d8647c77
1585d6310d
hex557951a1

1434014113 has 8 divisors (see below), whose sum is σ = 1725129920. Its totient is φ = 1164462480.

The previous prime is 1434014081. The next prime is 1434014119. The reversal of 1434014113 is 3114104341.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1434014113 - 25 = 1434014081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1434014119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5390898 + ... + 5391163.

It is an arithmetic number, because the mean of its divisors is an integer number (215641240).

Almost surely, 21434014113 is an apocalyptic number.

It is an amenable number.

1434014113 is a deficient number, since it is larger than the sum of its proper divisors (291115807).

1434014113 is a wasteful number, since it uses less digits than its factorization.

1434014113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10782087.

The product of its (nonzero) digits is 576, while the sum is 22.

The square root of 1434014113 is about 37868.3788007884. The cubic root of 1434014113 is about 1127.6763572889.

Adding to 1434014113 its reverse (3114104341), we get a palindrome (4548118454).

The spelling of 1434014113 in words is "one billion, four hundred thirty-four million, fourteen thousand, one hundred thirteen".

Divisors: 1 7 19 133 10782061 75474427 204859159 1434014113