Base | Representation |
---|---|
bin | 10100110111100011011… |
… | …110000011010001001111 |
3 | 12002002111202001001200111 |
4 | 110313203132003101033 |
5 | 141443403321242221 |
6 | 3014442234540451 |
7 | 205414600260250 |
oct | 24674336032117 |
9 | 5062452031614 |
10 | 1434040415311 |
11 | 50319a47a129 |
12 | 1b1b15297727 |
13 | a52ca0a125a |
14 | 4d59d4c8b27 |
15 | 27481843be1 |
hex | 14de378344f |
1434040415311 has 4 divisors (see below), whose sum is σ = 1638903331792. Its totient is φ = 1229177498832.
The previous prime is 1434040415303. The next prime is 1434040415329. The reversal of 1434040415311 is 1135140404341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1434040415311 - 23 = 1434040415303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1434040415341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102431458230 + ... + 102431458243.
It is an arithmetic number, because the mean of its divisors is an integer number (409725832948).
Almost surely, 21434040415311 is an apocalyptic number.
1434040415311 is a deficient number, since it is larger than the sum of its proper divisors (204862916481).
1434040415311 is an equidigital number, since it uses as much as digits as its factorization.
1434040415311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 204862916480.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 1434040415311 its reverse (1135140404341), we get a palindrome (2569180819652).
The spelling of 1434040415311 in words is "one trillion, four hundred thirty-four billion, forty million, four hundred fifteen thousand, three hundred eleven".
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