1434110220131 has 8 divisors (see below), whose sum is σ = 1450255582800. Its totient is φ = 1417965563520.

The previous prime is 1434110220119. The next prime is 1434110220161. The reversal of 1434110220131 is 1310220114341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1434110220131 - 2²² = 1434106025827 is a prime.

It is a super-2 number, since 2×1434110220131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1434110220097 and 1434110220106.

It is not an unprimeable number, because it can be changed into a prime (1434110220161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4645880 + ... + 4944938.

It is an arithmetic number, because the mean of its divisors is an integer number (181281947850).

Almost surely, 2^{1434110220131} is an apocalyptic number.

1434110220131 is a deficient number, since it is larger than the sum of its proper divisors (16145362669).

1434110220131 is an equidigital number, since it uses as much as digits as its factorization.

1434110220131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 353029.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1434110220131 its reverse (1310220114341), we get a palindrome (2744330334472).

The spelling of 1434110220131 in words is "one trillion, four hundred thirty-four billion, one hundred ten million, two hundred twenty thousand, one hundred thirty-one".