Base | Representation |
---|---|
bin | 10100110111100111101… |
… | …000011000101101001101 |
3 | 12002002200121102012010102 |
4 | 110313213220120231031 |
5 | 141444024204432141 |
6 | 3014453211220445 |
7 | 205416405565505 |
oct | 24674750305515 |
9 | 5062617365112 |
10 | 1434110233421 |
11 | 503225926548 |
12 | 1b1b34747725 |
13 | a530b6a8048 |
14 | 4d5a88a0a05 |
15 | 27487a3599b |
hex | 14de7a18b4d |
1434110233421 has 4 divisors (see below), whose sum is σ = 1434115526844. Its totient is φ = 1434104940000.
The previous prime is 1434110233393. The next prime is 1434110233453. The reversal of 1434110233421 is 1243320114341.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1207735060900 + 226375172521 = 1098970^2 + 475789^2 .
It is a cyclic number.
It is not a de Polignac number, because 1434110233421 - 210 = 1434110232397 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1434110232421) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2217080 + ... + 2789921.
It is an arithmetic number, because the mean of its divisors is an integer number (358528881711).
Almost surely, 21434110233421 is an apocalyptic number.
It is an amenable number.
1434110233421 is a deficient number, since it is larger than the sum of its proper divisors (5293423).
1434110233421 is an equidigital number, since it uses as much as digits as its factorization.
1434110233421 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5293422.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1434110233421 its reverse (1243320114341), we get a palindrome (2677430347762).
The spelling of 1434110233421 in words is "one trillion, four hundred thirty-four billion, one hundred ten million, two hundred thirty-three thousand, four hundred twenty-one".
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