Base | Representation |
---|---|
bin | 1101000010110000110001… |
… | …1111010111111011110011 |
3 | 1212202222220021211020111012 |
4 | 3100230030133113323303 |
5 | 3334431040432234220 |
6 | 50300113550341135 |
7 | 3010052650121531 |
oct | 320541437277363 |
9 | 55688807736435 |
10 | 14341105352435 |
11 | 462a035110634 |
12 | 173749b1ba7ab |
13 | 80048bb3b0b4 |
14 | 3781828b1151 |
15 | 19d0a2135ac5 |
hex | d0b0c7d7ef3 |
14341105352435 has 8 divisors (see below), whose sum is σ = 17209524411456. Its totient is φ = 11472752289600.
The previous prime is 14341105352389. The next prime is 14341105352443. The reversal of 14341105352435 is 53425350114341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14341105352435 - 210 = 14341105351411 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14341105352392 and 14341105352401.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16019714 + ... + 16891223.
It is an arithmetic number, because the mean of its divisors is an integer number (2151190551432).
Almost surely, 214341105352435 is an apocalyptic number.
14341105352435 is a deficient number, since it is larger than the sum of its proper divisors (2868419059021).
14341105352435 is an equidigital number, since it uses as much as digits as its factorization.
14341105352435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32998093.
The product of its (nonzero) digits is 432000, while the sum is 41.
Adding to 14341105352435 its reverse (53425350114341), we get a palindrome (67766455466776).
The spelling of 14341105352435 in words is "fourteen trillion, three hundred forty-one billion, one hundred five million, three hundred fifty-two thousand, four hundred thirty-five".
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