14341114342125 has 48 divisors (see below), whose sum is σ = 26206389331824. Its totient is φ = 7543819008000.

The previous prime is 14341114342123. The next prime is 14341114342133. The reversal of 14341114342125 is 52124341114341.

14341114342125 is a `hidden beast` number, since 1 + 4 + 3 + 4 + 1 + 1 + 1 + 434 + 212 + 5 = 666.

It can be written as a sum of positive squares in 8 ways, for example, as 7166532453444 + 7174581888681 = 2677038^2 + 2678541^2 .

It is not a de Polignac number, because 14341114342125 - 2¹ = 14341114342123 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14341114342125.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14341114342123) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 87230596 + ... + 87394845.

It is an arithmetic number, because the mean of its divisors is an integer number (545966444413).

Almost surely, 2^{14341114342125} is an apocalyptic number.

14341114342125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

14341114342125 is a deficient number, since it is larger than the sum of its proper divisors (11865274989699).

14341114342125 is a wasteful number, since it uses less digits than its factorization.

14341114342125 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 174625535 (or 174625522 counting only the distinct ones).

The product of its digits is 46080, while the sum is 36.

Adding to 14341114342125 its reverse (52124341114341), we get a palindrome (66465455456466).

The spelling of 14341114342125 in words is "fourteen trillion, three hundred forty-one billion, one hundred fourteen million, three hundred forty-two thousand, one hundred twenty-five".