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1434114535 = 5782349787
BaseRepresentation
bin101010101111010…
…1101100111100111
310200221112120022011
41111132231213213
510414113131120
6354150015051
750352525640
oct12536554747
93627476264
101434114535
1167657a527
12340347487
1319b1644a9
14d86726c7
1585d82c5a
hex557ad9e7

1434114535 has 16 divisors (see below), whose sum is σ = 1969214976. Its totient is φ = 982178208.

The previous prime is 1434114533. The next prime is 1434114557. The reversal of 1434114535 is 5354114341.

It is a cyclic number.

It is not a de Polignac number, because 1434114535 - 21 = 1434114533 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1434114497 and 1434114506.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1434114533) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3912 + ... + 53698.

It is an arithmetic number, because the mean of its divisors is an integer number (123075936).

Almost surely, 21434114535 is an apocalyptic number.

1434114535 is a deficient number, since it is larger than the sum of its proper divisors (535100441).

1434114535 is an equidigital number, since it uses as much as digits as its factorization.

1434114535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50622.

The product of its digits is 14400, while the sum is 31.

The square root of 1434114535 is about 37869.7047123423. The cubic root of 1434114535 is about 1127.7026798732.

Adding to 1434114535 its reverse (5354114341), we get a palindrome (6788228876).

The spelling of 1434114535 in words is "one billion, four hundred thirty-four million, one hundred fourteen thousand, five hundred thirty-five".

Divisors: 1 5 7 35 823 4115 5761 28805 49787 248935 348509 1742545 40974701 204873505 286822907 1434114535